x^2-8,8x+3=0

Solution for x^2-8,8x+3=0 equation:

x^2-8.8x+3=0

a = 1; b = -8.8; c = +3;
Δ = b2-4ac
Δ = -8.82-4·1·3
Δ = 65.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.8)-\sqrt{65.44}}{2*1}=\frac{8.8-\sqrt{65.44}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.8)+\sqrt{65.44}}{2*1}=\frac{8.8+\sqrt{65.44}}{2}
$